Buoyancy - a comparison between Gravity and the Standard Vibration Model

This is the model of buoyancy using Newtonian Mechanics. It is easy to see how this simple model captures the community communal approval.  

Tomorrow I will show how the Standard Vibration Model does a better job of describing what is observed in atmospheric interactions without using gravity or mass. 

Anonymous has left a new comment on your post "The N-Body Problem":

Now, buoyancy.

Buoyancy does not fly in the face of gravity. Gravity, when acting on an object in isolation, holds. The theory of gravity says nothing more than this... that two masses, when considered in isolation, attract one another with some force. There might be other interactions adding additional forces, but somewhere in the big pile of forces acing on a mass is a contribution from gravity, and it conforms to a simple equation.

Buoyancy is a phenomenon that occurs in a large, complex system... A single solution to the simple 2-mass gravity law is not suffucicient in this situation, and nobody backing gravitational theory is saying that it is. But it does contribute in an important way. Allow me to attempt to explain...

If we consider the balloon and earth in complete isolation, it would accelerate downward at G*m-sub-earth/r-sub-earth-balloon^2, as expected.

But this isn't a two body system. There is a third player... air. And in this system, the three bodies are acting on each other. The gravitational force between air and the balloon can be neglected, since the balloon is so small in this instance and the air is so widely distributed (I hope we don't conflict on that assumption... but if we do, I'll happily defend it).

So let's start with the air. Being acted on by gravity, it is all trying to be pulled downward. This is creating pressure at all places within the air, at increasing values at lower altitudes, since there is more weight on top of the air at lower heights. This pressure is acting against gravity. It is the resistance of the air to being compressed into a singularity, primarily driven by kinetic forces of the matter being compressed. Everywhere there is a force pushing down (gravity) and everywhere there is a force pushing up resisting it. Thus we acheive equilibrium and a stable atmosphere.

Enter the balloon. Imagine, if you will, we identify the spherical surface, centered at the earth's origin, who's radius extends just to the bottom of the balloon. Thus, we can talk about the air beneath that altitude (which I'll call lower air), and the air above that altitude (higher air). So the lower air is all the air around the world beneath the altitude of the balloon, and higher air is the rest (which is where the balloon is). Everywhere over earth's surface, the lower air is pushing up at a certain force... the force required to hold the higher air bay... exactly the same force, but opposite in direction, as gravity is generating from the higher air. Without the balloon, it's a uniform equillibrium. But now, in one cylindrical column of higher air, there's a balloon... a balloon that is lighter than the surrounding air.

So now there's a particular place where the higher air is lighter. And so the lower air is no longer in equilibrium at that place. It's pushing up with the same force as all the rest of the lower air, but the air above it in that particular spot is pushing down with less force due to the lighter mass balloon. And so the net force, the combination of the upward pressure and the gravitationally-induced downward weight, is non-zero, and upward acceleration results.

This continues until a new equilibrium between air pressure and gravity is reached, which will occur when the balloon rises to a state of equi-density with it's surrounding.

And all of this was explained nicely with gravity as a key contributor.


End of Anonymous' description.  
------------------
The Standard Vibration Model


It is assumed that the reader has already read the papers 
The Structure of Baryons
Variables Involved in Baryonic Motion


NASA Heavy lift balloons
The interesting thing about these heavy lift balloons is that they are capable of carrying a 1000-kg instrument to approximately 33 km giving little or no day/night altitude variation and ultimately 100-day flights[1].

At launch these balloons are filled with helium to 5% of the volume of the balloon. Any more than that and the balloon would rupture during the ascent. As the balloon rises in the atmosphere the helium expands to fill 100% of the volume of the balloon. The balloons are corrugated allowing for this expansion.

This would require the expansion of the helium atoms during ascent. This would mean the length of the gluon between quarks is a shorter length before launch and a longer length at altitude. The distance between atoms remains the same allowing for a smooth expansion.

I am going to add a drawing here to explain the distance continuity between helium atoms.

Literally the helium expands. There is almost no leakage since the helium atoms are now larger than the holes in the balloon. They have to pop the balloon to return the payload back to Earth.

------------

[1] NASA Heavy Lift Balloon Program

http://sites.wff.nasa.gov/code820/balloonroadmapreport.pdf