Wednesday, October 8, 2008

Free falling bodies

So If I understand the problem correctly, would two objects of different density dropped in the ISS, fall at different rate?

The major force on the above problem is the angular velocities of the two objects are the same as the space station and all will maintain the same orbit around the Earth. These three objects are falling at different rates but the angular velocity is more significant in this setup of the problem. Density has little to do with orbital periods, velocity is more significant here.

I would like to change the feather to a ball of water. Each ball is 1 kg.

What we would need to do is reduce the angular velocity of the lead ball and the ice ball to 0 km/sec in relation to a point on the Earth's surface. When this occurs the two objects are now falling to maintain their density.

Here the lead ball would turn to liquid, pass through the atmosphere and splat in the ocean. There it would cool again to a solid and fall to the ocean floor. It would continue falling for many eons through the sand, mantle to the core of the Earth. This is where it would meet its level of disbursement.

Whereas the water would start as ice and become vapor quickly. As a vapor it would disperse/equalize with other water vapor at its density level. In the high level atmosphere is where it would meet its level of disbursement. As it cooled it would then rain. The water would never have an altitude less than the ocean floor.

I was reading a paper on multiple instruction multiple data computing systems. What I got from it was that this is a multiple force problem. These forces; density and thermodynamic work together to create the bounds of the problem. When is the object is at a level of disbursement?

We cannot remove one of the forces from the problem to simplify the problem, because we would no longer have a valid problem/solution. It needs both thermodynamics and density to do this.

Both balls would have other forces acting upon them. For example both would have hydrodynamic issues of turning into a teardrop shape during decent. But I don’t see this as a major force acting upon the problem. I could be wrong.

So I see a summation of forces acting upon an object to determine its altitude of disbursement. But I can definitively say there is no gravity in this problem.

Question: What about this video?

Answer: Cinci, again you bring up a good point. And something that is difficult to explain in my model, but I will give it a try. First, this video is not a empirical test of falling bodies. We don't know the time it took to fall. Nor can we tell if the two object did hit the ground at the same time. We would also need the distance traveled. This is a good example of two different objects traveling in a vacuum.

Here what we are seeing needs an explanation of the moon's forward velocity. Here the Astronauts are on the face of the moon. The face of the moon is like the front of a NASCAR car. The moons forward motion is so great that it hits the hammer and feather. Also the distances here are not great so we cannot see the difference in density of the two objects. If these objects were release at 1000km altitude from the moon, we would see a different result.

The equations for this are found in chemistry. It is called Specific Gravity. rather a misnomer, but we work with what we are given. It really is the density of the objects and the density of the medium that are the main forces here.

I know that is rather weak, but those density(specific gravity) solutions work in chemistry, why not in physics? We just need to evaluate the media. Not every media is water.
Post a Comment